a charged particle enters a uniform magnetic field and follows the circular path at right angles to the magnetic field the field exists for a length equal to 1.5 times the radius of the circular path of the particle the particle will be deviated from its path by
1- 90 degrees
2 - 30 degrees
3 - 180 degrees
(please explain)
Anonymous:
I kinda didn't understand what the question means. Someone enlighten me!
What's the answer? Is it Π-1.5 radians?
Or Π+1.5 radians?
the answer is 180 degrees but i dont know how
Answers
Answered by
216
Please see diagram.
As I understand the question, let the uniform magnetic field B be into the plane of the diagram. Let the charged particle +q enter from one side of magnetic field with a velocity v.
The force on q is F = q v x B.
It is a vector cross product. The force is in the direction towards the center of circle and supplies the centripetal force. Since force and acceleration on q are in perpendicular direction to velocity v, velocity does not change.
The particle q moves in a circle and exits the magnetic field at the other end of the diameter at the entry point. Hence the angle turned by the particle is 180 degrees.
As I understand the question, let the uniform magnetic field B be into the plane of the diagram. Let the charged particle +q enter from one side of magnetic field with a velocity v.
The force on q is F = q v x B.
It is a vector cross product. The force is in the direction towards the center of circle and supplies the centripetal force. Since force and acceleration on q are in perpendicular direction to velocity v, velocity does not change.
The particle q moves in a circle and exits the magnetic field at the other end of the diameter at the entry point. Hence the angle turned by the particle is 180 degrees.
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click on thank you and select best answer
so there is no use of 1.5 times
Answered by
33
The particle will be deviated from its path
By 180
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