Question

a charged particle enters in a magnetic field of thousand Newton per ampere metre with a velocity of 10 power 6 metre per second calculate the force acting on the charge if it enter parallel to the field perpendicular to the field in making an angle of 60 degree with the field magnitude of charge equal to 3.2 into 10 to the power minus 19 coulomb​

Answer 1

Explanation:

Force=

$16 \sqrt{3 \times {10}^{ - 11} \: newton$