Question

a charged particle having a charge of minus 3 microcoulomb is placed close to a sheet of charge having surface charge density 5 into 10 raise to power 6 cm find the force of attraction between the particles and the sheet of charge​

Answer 1

Answer:

Explanation: A charged particle having a charge of – 2.0 × 10^-6 is placed closed to a non-conducting plate having a surface charge density 4.0 × 10^-6 C/m^2. ... due to a charge conducting sheet = σ/2ε base 0 Again Force of attraction between particle & plate = Eq ... A copper disc 20 cm in diameter and turns 1000 times to form a coil.