Question

A charged particle is observed traveling in a circular path of radius R in a uniform magnetic field. If the particle was traveling twice as fast, the radius of the circular path would be

8R.
R/4.
R/2.
2R.
4R.
expanation also

Answer 1

For circular motion in Mag field. $qvB = \frac{mv^{2}}{R}$
Thus $R = \frac{mv}{qB}$

This implies R must get doubled when the velocity is doubled.

Ans- 2R

Answer 2

Answer:

The correct answer is option (d) 2R.

Explanation:

Given:

A charged particle exists observed traveling in a circular path of radius R in a uniform magnetic field.

To find:

the radius of the circular path.

Motion in a constant magnetic field

If the velocity of the charged particle exists perpendicular to the B field the motion exists circle with a radius R=mv/qB.

For circular motion in Mag field.

$q v B=\frac{m v^{2}}{R}$

Thus R=mv/qB.

This implies R must get doubled when the velocity exists doubled.

Where, Radius R of the circular way of a charged particle q of mass m, moving at constant speed v, in a uniform magnetic field B: R = mv/qB.

Therefore, the correct answer is option (d) 2R.

SPJ2