Question

A charged particle is projected in a magnetic field B =(3 i +4 j )×10-² T and the acceleration is found to be a =(x i+2 )m/s 2. The value of x is :​

Answer 1

Answer:

x=3-8

Explanation:

Correct option is

A

-8/3 m/s2

F=q(V×B)

So F⊥B

∴F⋅B=0

ma⋅B=0

a⋅B=0

(xi+2j)⋅(3i+4j)=0

3x+8=0

x=3−8