Question

a charged particle is thrown in a magnetic field of 2T with a velocity of 3J.Its path is??​

Answer 1

Answer: it’s a pleasure to help you friend..

Explanation:

Given :   v=2×10^3  m/s  ,     B=1.5T

As the particle passes undeflected, thus electric force is balanced by the magnetic force acting on the particle.

∴   qE=q(v×B)            

⟹   E=Bv=1.5×2×10^3

=3×10^3  NC ^ −1

hope it’s useful friend..

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