Question

A charged particle moving in a circular path when enters at right angle to the magnetic field. then radius of the circular path will be​

Answer 1

Answer:

Let the uniform magnetic field B be into the plane of the diagram.  Let the charged particle +q enter from one side of magnetic field with a velocity v.

The force on q is F = q v x B.

It is a vector cross product.  The force is in the direction towards the center of circle and supplies the centripetal force.  Since force and acceleration on q are in perpendicular direction to velocity v, velocity does not change.

The particle q moves in a circle and exits the magnetic field at the other end of the diameter at the entry point.  Hence the angle turned by the particle is 180 degrees.

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Answer 2

Answer:

1/2 of diameter

hop this will work