Physics, asked by renusanai77, 5 months ago

A charged particle moving perpendicular to magnetic field experiences a magnetic force

Options
in the direction of field

in the direction opposite to that of field

in the direction perpendicular to both the field and its velocity

none of the above


plz​

Answers

Answered by Anonymous
2

\huge \underline \green{\sf{ Answer :- }}

  • \small \underline  {\sf{ in \  the \  direction \  perpendicular \ to \  both \  the \  field \   and  \  its \  velocity}}

As, F=q(v×B)

Thus, force is perpendicular to both the vectors velocity and magnetic field

Answered by hotelcalifornia
0

In a moving charged particle, the magnetic force is experienced in the direction perpendicular to the field and in the direction of the particle's velocity.

Explanation:

  • By the right-hand rule, the charge and magnetic field velocity will have a direction that is perpendicular to the magnetic force on a free-moving charge.
  • You can calculate the force by multiplying the charge by the vector product of velocity and magnetic field.
  • Because the magnetic field does not point along the direction of the source of the field, it points perpendicularly.
  • The magnetic field is perpendicular to the direction of the magnetic force.
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