A charged particle of charge 1 mC and mass 2g is moving with a speed of 5m/s in a uniform magnetic field of 0.5 tesla. Find the maximum acceleration of the charged particle
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Answer:
a=1.25m/s²
Explanation:
maximum force on the particle when the particle is moving perpendicular to the magnetic field.
F = Bqv
acceleration = F/m = 0.5*0.001*5/0.002
a= 5/4 = 1.25 m/s²
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