Question

A charged particle of charge q and mass M is released from rest in the uniform electric field is neglecting the effect of gravity the kinetic energy of a charged particle after the time second is

Answer 1

Explanation:

Force on particle=F=qE

Hence, acceleration of particel=a=

m

F

=

m

qE

Initial speed=u=0

Hence, final velocity=v=u+at=

m

qEt

Kinetic energy=K=

2

1

mv

2

=

2

1

m(

m

qEt

)

2

⟹K=

2m

E

2

q

2

t

2