Physics, asked by jaypalsinh9579, 1 year ago

A charged particle of charge q and mass m is released from rest in an uniform electric field E. Neglecting the effect of gravity, the kinetic energy of the charged particle after time t seconds is

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Answered by Anonymous
5

Answer:

Hii mate

Explanation:

✒1/2m [(qE/m + g)t]^2 Joule.

✒ If the effect of gravity is neglected then, ma =qE.

✒Then from kinematic .

✒The acceleration of the particle is thus qE .

✒ qE + mg = ma a = qE/m + g.

✒v = 0 + at. v = (qE/m + g)t. 3) K.E =1/2mv^2. = 1/2m .

I hope it's helpful ❤✌✌❣

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