Question

A charged particle of charge q and mass m is
released from rest in an uniform electric field
E Neglecting the effect of gravity, the
kinetic energy of the charged particle after
time 't' seconds is:
​

Answer 1

Answer:

when Charged Particle at rest in uniform field -

W=Q\cdot \Delta v

-When charge q is released in uniform electric field  then its acceleration a=\frac{qE}{m}  (is constant)

So its motion will be uniformly accelerated motion and its velocity after time t is given by

v=at=\frac{qE}{m}t \Rightarrow KE= 1/2mv^2= 1/2(\frac{qE}{m})t= \frac{q^2E^2t^2}{2m}

Explanation: