Question

A charged particle of mass 2 MG hand in air in an electric field of strength 4 Newton per coulomb directed upwards the charge on the particle would be

Answer 1

mass = 2×10^-6kg

E= 4 newton per coulomb

F =qe...eq(1)

and. F =mg....eq(2)

comparing both

mg=qe

then

q=mg/E

substitute the values and answer will be 4.9×10^-6 coulomb

hope it helps

Answer 2

Answer :-

◾Provided :-

▪️Mass of Particle = 2mg or $\sf{ 2\times 10^{-6} \: kg}$

▪️Electric Field Strength = 4 N/C

◾Now as we know that

▪️F = qĒ

◾Where

▪️q = total charge

▪️F = force

▪️Ē = Electric Field Strength

◾So , To find out charge we will assume that the particles is in equilibrium

→ Magnitude Total force upward = Magnitude of Total force Downward

▪️Total force Downward

= Mg

$= 2\times10^{-6} \times 9.8$

$= 19.6 \times 10^{-6}$

◾Now (- Downward force) = qĒ

$\implies -(19.6 \times 10^{-6} )= q \times 4$

$\implies q = \dfrac{ -19.6 \times 10^{-6}}{4}$

$\implies q =- 4.9 \times 10^{-6}$

$\star\bold{So\: charge \:= -4.9 \times 10^{-6} }$