Physics, asked by katherine1212, 10 months ago

A charged particle of mass m, and charge qı is
revolving in a circle of radius r. Another charged
particle of charge q, and mass m, is situated at the
centre of the circle. If the velocity and time period of
the revolving particle be v and T repectively then
need solution ​

Answers

Answered by CuriousTesla
1

ANSWER

Both charges are either both positive or both negative(since answers has the product q

1

q

2

inside square root). Hence, circular motion is not possible. So either q

1

or q

2

should be negative.

According to the diagram,

r

m

1

v

2

=

4πϵ

0

1

r

2

q

1

q

2

⟹v=

4πϵ

0

m

1

1

r

q

1

q

2

On putting, v=rω and ω=

T

, we can find out:

T=

q

1

q

2

16π

3

ϵ

0

m

1

r

3

BRAINLIEST PLS ..TOOK ME 5 HOURS.

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