Physics, asked by ritusingh1128, 2 months ago

A charged particle plastic ball of mass 8.4 * 10^-16 kg is found to remain suspended in uniform electric field of 2.6*10^ 4 v/m.calculate charge?​

Answers

Answered by jaswanthjanu
7

Answer:

F=E*q

q=F)E

F=mg. f=8.4 * 10^-16*9.8=

Explanation:

82.32 *10^-16=f

E=2.6*10^4

q=f/E

q=31.66*10^-12

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Answered by dipalipatil301281
1

Answer:

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