Question

A charged particle q is moving in the presence of a magnetic field B which is inclined to an angle 30° with the direction of the motion of the particle. Draw the trajectory followed by the particle in the presence of the field and explain how the particle describes this path.

Answer 1

The path described by the particle in magnetic field will be helical.

Explanation:

The force on a charged particle in a magnetic field is given by

F = q (v x B)  

• Where q = charge of the particle ,
• v = velocity of particle and B is the magnetic field in that region.
• The equation F = q (v x B) shows that the force exerted on a charged particle in a magnetic field is perpendicular to the direction of the magnetic field.

• If velocity has a component along B, this component will not change as the motion along the magnetic field remain unaffected by the field.
• The motion of particle in a plane perpendicular to B produces a helical motion.
• Thus the described path will be helical.

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A particle of charge 1 uC is at rest in a magnetic field B = -2k tesla. Magnetic Lorentz force on the charge  particle with respect to an observer moving with velocity j = -5i ms' will be?

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Answer 2

Answer:

the direction of the motion of particle is helical structure in a vertical path perpendicular to x axis

Explanation:

when a charged particle moves in the presence of magnetic field at any arbitrary angle has two concurrent motions

• Therefore a linear motion in the direction of B vector and a circular motion in a plane perpendicular to B Vector. Hence , the resultant path of the charged particle will be a helix with its axis along the direction of vector
• V11 -> acts along the direction of B vector
• V11 = V cos theta
• V perpendicular=V Sin theta
• Due to this component of velocity, the charged particles experiences a force which act perpendicular to both v perpendicular and Band this force makes to more the charge hellical.