Question

A charged particle q is moving with a speed v perpendicular to the magnetic field of induction B. Find the radius of the path and time period of the particle.

Answer 1

Answer:

r = mv/ qB

time period, t = 2πm/ qB

Answer 2

Force on a charged particle inside magnetic field = qvBsin theta

Since theta = 90 degree (given)

Force = qvBsin90

Force = qvB

Since force on a charged particle = centripalforce exerted on a particle

qvB = mv^2/r

r (radius of the path) = mv/qB

Where m= mass of particle

V= speed of a particle

q= charged on a particle

B= magnetic field

Also Time period = (2× 22/7×r)/v

Putting value of r in time period

We get:

T= (2×22/7×m)/(q×B).