Question

A charged particles of mass 4kg and charge 2C is projected with initial speed 20m/s at an angle 30° with the horizontal. A uniform electric field of intensity 10N/C is present in the region in the +y-direction. Find the maximum height attained by the particle? (Acceleration due to gravity is g=10m/s^2 in y-direction):

Answer 1

Given that,

Mass = 4 kg

Charge = 2 C

Angle = 30°

Speed = 20 m/s

Electric field = 10 N/C

We need to calculate the acceleration

Using formula of electric field

$E=\dfrac{F}{q}$

$a=\dfrac{Eq}{m}$

Put the value into the formula

$a=\dfrac{10\times2}{4}$

$a=5\ m/s^2$

We need to calculate the time

Using formula of time of flight

$t=\dfrac{2u_{y}}{g}$

$t=\dfrac{2\times20\cos30}{9.8}$

$t=3.53\ sec$

We need to calculate the maximum height attained by particle

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$s=20\times3.53+\dfrac{1}{2}\times5\times(3.53)^2$

$s=101.75\ m$

Hence, The maximum height attained by particle is 101.75 m

Learn more :

Topic : projectile

https://brainly.in/question/5339166