A charged spherical conductor has a surface charged density of 0.07 units . When its charge is increased by 4.4 units the charged density changed by 0.014 units. Find the radius of sphere and initial charge on it
Answers
Answered by
0
hey buddy here is your answer
initial charge density =0.07
Q/4πR^2=0.07............................(I)
Now when Q is increased
Q+0.44/4πR^2=0.21...................(II) dividing (1) and (11) we get. Q+0.44/4πR^2*4πR^2/4=3. Q+0.44=3Q. Q=0.22. substitute in equation( I )we get R=0.5. if you satisfied with my answer than mark my answer as the brainiest answer
Similar questions