Question

a charges of 6 c passes through the cross section of copper wire in are minute find current through the wire​

Answer 1

Answer:

• 0.1 Ampere is the required answer .

Explanation:

Given:-

• Charge ,Q = 6 C
• Time taken ,t = 1 min = 60 s

To Find:-

• Current through the wire ,I

Solution:-

As we know that current is defined as the flow of charge .

• I = Q/t

where,

• I denote Current
• Q denote charge
• t denote time

Substitute the value we get

→ I = 6/60

→ I = 1/10

→ I = 0.1 A

• Hence, the current flowing through the wire is 0.1 Ampere .

Answer 2

Given : The amount of charge passes through a cross section of copper wire is 6 C [ Q , Electric Charge ] & The total time taken is 1 minute [ T , Time taken ] .

Exigency To Find : The Current passes through wire [ I , Current ] .

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

Given that ,

⠀⠀⠀⠀⠀⠀▪︎⠀The amount of charge passes through a wire is 6 C [ Q , Electric Charge ]

⠀⠀⠀⠀⠀⠀▪︎⠀The total time taken is 1 minute [ T , Time taken ] .

⠀⠀⠀⠀⠀⠀⠀⠀⠀Converting Time taken from minutes to second :

$\qquad:\implies \sf Total \:Time\:Taken\:\:[\ T\ ] \:= 1 \: min\:$

$\qquad:\implies \sf Total \:Time\:Taken\:\:[\ T\ ] \:= 1 \: min\:or\:\:60\:sec$

$\qquad:\implies \sf Total \:Time\:Taken\:\:[\ T\ ] \:= 60 \: sec\:\qquad \bigg\lgroup \sf{ 1 \: minute \:= 60\:second\:}\bigg\rgroup$

$\qquad:\implies \bf Total \:Time\:Taken\:\:[\ T\ ] \:= 60 \: sec\:$

$\dag\:\:\sf{ As,\:We\:know\:that\::}\\\\\qquad \bigstar \bf \:\: Electric \:Current\:(\ I \ ) \:\:: \:\sf The \:rate \:of\:flow \:of\:Electric \:charge \:(\ Q\ ) \: .\\ \qquad \leadsto \:\sf\:The \:S.I \:unit\:of\:Current \:is\:\bf \: Ampere\:\:[\ A \ ] \: \sf .\\\\ \qquad\maltese\:\:\bf Formula \:for\:Current\::$

$\qquad \dag\:\:\bigg\lgroup \sf{ \:\:I \:\:= \:\:\dfrac{Q}{T}\:\:\:}\bigg\rgroup$

⠀⠀⠀⠀⠀Here , I is the Current passes through wire , Q is the Electrical charge & T is the Total time taken.

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad:\implies \sf I = \dfrac{Q}{T} \:$

$\qquad:\implies \sf I = \dfrac{6}{60} \:$

$\qquad:\implies \sf I = \cancel {\dfrac{6}{60}} \:$

$\qquad:\implies \sf I = \dfrac{1}{10} \:$

$\qquad:\implies \sf I = \cancel {\dfrac{1}{10}} \:$

$\qquad:\implies \bf I = 0.1 \:$

$\qquad :\implies \frak{\underline{\purple{\: I = 0.1 \:A \:or\:\:Ampere }} }\:\:\bigstar$

⠀⠀⠀⠀⠀⠀▪︎ I is the Current passes through wire = 0.1 A or Ampere .

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:The\:current \:passes\:through \:wire\: \:is\:\bf{0.1 \:A \:or\:\:Ampere }}.}}$