Question

A charges of 9 mC is placed in a uniform electric field of 10 N/C. Find the
value of force experience by charge particle. (90 x 10-3N)
please answer it urgent​

Answer 1

Answer:

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Q.)What is the force between two small charged spheres having charges of 2 ×10-7C and 3 × 10–7C placed 30 cm apart in air?

Answer:

Given:

Repulsive force of magnitude 6 × 10−3 N

Charge on the first sphere, q1 = 2 × 10−7 C

Charge on the second sphere, q2 = 3 × 10−7 C

Distance between the spheres, r = 30 cm = 0.3 m

Electrostatic force between the spheres is given by the relation:

F = (1/4πε0). (q1q2)/ (r2)

Where, ε0 = Permittivity of free space and (1/4πε0) =9 × 109 Nm2C−2

Therefore, force F = (9 × 109 × 2 × 10−7)/ ((0.3)2)

= 6 × 10−3N

Hence, force between the two small charged spheres is 6 × 10−3 N. The charges are of same nature. Hence, force between them will be repulsive.