Question

A check whither (x+2) (x+1) = (x-1) (x+3) is a quadratic or not​

Answer 1

Answer:

No

Step-by-step explanation:

(x + 2) (x + 1) = (x - 1) (x + 3)

Expand this using the identity:

• 『(x + a) (x + b) = x² + x(a + b) + ab』

Applying this identity for Left Hand Side,

(x + 2) (x + 1)

= x² + x(2 + 1) + 2(1)

= x² + 3x + 2

Now, again applying the same identity to Right Hand Side;

(x - 1) (x + 3)

= x² + x(3 - 1) + 3(-1)

= x² + 2x - 3

In the question it is given that LHS = RHS

→ x² + 3x + 2 = x² + 2x - 3

→ 3x + 2 = 2x - 3

→ 3x - 2x = -3 - 2

→ x = -5

The equation could be easily solved without splitting of middle term or applying Quadratic formula.

∴ (x+2) (x+1) = (x-1) (x+3) is not a Quadratic Equation.

Answer 2

Step-by-step explanation:

x²+x-2x+2=x²+3-x+3x

-x+2=3+2x

3x=-1