Question

A cheeta starts from rest accelerates at 2m/s×s at 10 seconds.calculate its final velocity and distance travelled

Answer 1

initial velocity is 0

i)v=u + at
=20m/s

ii)S=ut+at/2
=20/2
=10m

Answer 2

Initial Velocity (u) = 0

Acceleration(a) = 2m/sxs

Time Taken = 10secs

for constant acceleration:

v = u + at

=> v = 0 + 2 x 10

=> v = 20m/s

also for constant acceleration:

S = ut + 1/2 at^2

=> S = 0xt + 1/2 x 2 x t^2

=> S = 1/2 x 2 x 100

=> S = 100m