Question

a cheetah can accelerate from rest at rate of 4m/s. what will be the velosity attained it in 10s and how far it will travel in this duration

Answer 1

Explanation:

v=u+at

s=ut+1/2at^2

apply these two formula respectively and you will get the ans

Answer 2

Answer:

$\huge\red{HELLO\:MATE}$

Initial velocity of cheetah(u) = 0m/s.

= 0m/s.Acceleration(a) = 4m/s.

Time (t) = 10s.

Final velocity (v) = ?

Now v = u + at .

So , v =( 0 + 4 ×10)m/s

Therefore v = 40m/s.

Also, s = ut + 1/2at^2 .

So , s = (0 × t + 1/2 × 4 × 10 × 10).

Therefore s = 200m.