Question

A cheetah can accelerate from rest at the rate of 4ms-2?what will be the velocity attained by it in 10s

Answer 1

By formula:

a=(v-u)/t

v=u+at

v=0+4*10

v= 40 m/s

v=final velocity

u=initial velocity

a=acceleration

t=time

Answer 2

v=u+at

v-->final velocity. = ?

u-->initial velocity. = 0m/s

a-->acceleration. = 4m/s^2

t-->time. = 10m/s

v=0+4*10

v=40m/s

Ans===>> 40m/s