Question

a cheetah can acclerate from rest at the rate of 4m/s^-2.
(a)what will be the velocity attained by it in 10s.
(b)how far will it travel in this duration?

Answer 1

Hii..
Here is your answer..

Solution:-
Initial velocity=0(as he start from rest)
Acceleration=4m/s^2
Now,
a) Velocity attained in 10s =
$= > v = u + at \\ = > v = 0 + 4 \times 10 \\ = > v = 40$
B)How far he will travel in this duration=
$= > {v}^{2} = {u}^{2} + 2as \\ = > {(40)}^{2} = {(0)}^{2} + 2 \times 4 \times s \\ = > 1600 = 0 + 8s \\ = > s = \frac{1600}{8}$
$= > s = 200m$
Hope it helps uh....✌️✌️✌️