Question

A cheetah chases a deer, which is 100m ahead. the time in which deer takes 10 leaps, cheetah takes 6 leaps only. in one leap, the deer cover 1 meter while the cheetah covers 2 meters. in how many leaps would the cheetah catch up the deer

Answer 1

Find the ratio of the leap

Cheetah : deer = 6 : 10

Find the ratio of the distance covered:

The Cheetah can do 2m per leap and the deer can do 1m per leap.

⇒ Cheetah : deer = 6 x 2 : 10 x 1

⇒ Cheetah : deer = 12 : 10

⇒ Cheetah : deer = 6 : 5

⇒ For every 6m the cheetah covered, the deer covered 5m

Find the number of 6 leaps that the Cheetah need to make to catchup with the dear:

Difference in leap distance = 6 - 5 = 1 m

Difference in distance between them = 100m

Number of leaps needed = 100 ÷ 1 = 100

⇒ We need 100 of the 6 leaps

Find the total leaps the Cheetah need to make:

100 x 6 = 600 leaps

Answer: The Cheetah will catch up with the deer in 600 leaps

Answer 2

Ratio of the leaps -

Cheetah : Deer = 6 : 10

Finding the ratio of distance covered -

Cheetah = 2 metre per leap

Deer = 1 metre per leap

Cheetah : Deer

6 x 2 : 10 x 1

12 : 10

Simplifying by 2

6 : 5

Cheetah covered = 6 metres .

Deer covered = 5 metres.

Difference in leap distance = 6 - 5 = 1 metre

Difference in distance between them = 100 m (given)

Number of leaps needed = 100 ÷ 1 = 100 leaps .

Finding total leaps cheetah need to make -

100 x 6 = 600 leaps.

$\bold{Cheetah \: would \: catch \: up \: in \: 600 \: leaps}$