A cheetah is the fastest animal on land and can achieve a peak velocity of 100 km per hour upto less than 500 m .If a cheetah spots it's prey at a distance of 100 m , What is the minimum time it will take to get it prey
Answers
Explanation:
solution :
peak speed of cheetah = 100 km/hr
First we will convert the speed into m/s
therefore ,
100 km/hr = 100 *1000 m / 60 *60
( because 1km = 1000 m and 1hr = 60 mimutes and 1 minute = 60 seconds )
100km/hr = 100*5/18 m/s
= 500 /18 m/s
Therefore , Peak speed of Cheetah = 500/18 m/s
Distance between cheetah and its prey = 100 m
Therefore ,
time taken by cheetah to reach its prey at a distance of 100 m = distance between cheetah and prey / velocity of cheetah
= 100 /( 500/18) seconds
= 100*18/500
= 18/5
= 3.6 seconds
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It's given,
A cheetah is the fastest land animal and it can achieve a peak velocity of 100 km per hour up to distances less less than 500 metres.
We can write 100 km as 27.78 m/s. [100x1000/60x60]
We know,
Formula to calculate speed:
Speed (v) = Ditance/time (d/t)
∴ Time = Distance/Speed (d/v)
= 100/27.78
= 3.6 s
∴ The minimum time it will take to get it's prey is 3.6 second