Question

. A cheetah is the fastest land animal and can achieve a peak velocity of 100 km/h up to distances less than 500 m. lf a cheetah sports its prey at a distance of 100 m, what is the minimum time it will take to get its prey, if the average velocity attained by it is 90 km/h?

Answer 1

☆Hey friend!!!☆

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Here is your answer ☞
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$we \: know \: that \\ \\ = > time \: = \frac{distance}{velocity} \\ \\ so \\ \\ = > \: time \: = \frac{100m}{90 \frac{km}{h} } \\ \\ = > time \: = \frac{100m \times h}{90000m} \\ \\ = > time = {900}^{ - 1} h \\ \\ = > time = \frac{60}{900} min \\ \\ = > time = \frac{1}{30} min = \frac{60}{30} sec \\ \\ = > time = 2sec \: \: \: \: ........answer$

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Hope it will help you ☺☺
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Devil_king ▄︻̷̿┻̿═━一

Answer 2

Hey there!

It's given,

A cheetah is the fastest land animal and it can achieve a peak velocity of 100 km per hour up to distances less less than 500 metres.

We can write 100 km as 27.78 m/s.   [100x1000/60x60]

We know,

Formula to calculate speed:

Speed (v) = Ditance/time (d/t)

∴ Time = Distance/Speed (d/v)

           = 100/27.78

           = 3.6 s

∴ The minimum time it will take to get it's prey is 3.6 second.

Hope it helps You!