A cheetah running at a speed of 90 km / hr spot deer at a distance of 720 m. Find the rate at which he accelerates and catch prey in 20 sec.
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Answer:
2.2m/s^2
Explanation:
We know the basic equation s=ut+1/2at^2
here s=720m,u=90km/hr=25m/s,t=20s
720=25*20+1/2*a(20)^2
=2.2m/s^2
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