Question

A cheetah starts from rest and accelarates at 2 m/s^2 for 10 seconds. Calculate
a] the final velocity
b] the distance travelled

Answer 1

Answer:

a=2m/s^2

t=10 sec.

V =u+at

v= 2 × 10=20 m/s

b.S=ut+1/2at^2

s=1/2 × 2 × 10 ×10

s=100 m

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Answer 2

Answer:

a) acceleration = a = 2m/s²

starting velocity = u = 0m/s

final velocity = v = ?

time = t = 10 sec

a = v-u/t

2 = v-0/10

2×10 = v

20 m/s = v

final velocity = v = 20m/s

b) velocity = v = 20m/s

time = t = 10 secl

distance = d = ?

v = d/t

v × t = d

20×10 = d

200d

the distance traveled is = d = 200 metres