Question

A cheetah starts from rest and accelerates at
2 m/s2 for 10sec calculate
The final velocity
The distince traveled​

Answer 1

a = 2m/s²

t = 10 sec

u = 0 m/s

v = ?

s = ?

v = u + at

= 0 + 2*10

v = 20m/s

.....,.................

s = ut + 1/2 at²

= 0*10 + 1/2*2*(10)²

s =100m.............

Answer 2

Answer:

final velocity:

v=?

u=0m/s

t=10s

a=2 m/s

now

v=u+ at

v= 0+ 2 x 10

v=20 m/s

therefore final velocity is 20 m/s

distance traveled:

v=20 m/s

u=0 m/s

a= 2m/s

s=?

v²=u²+ 2as

20²= 0²+2 x 2 x s

400/4= s

s=100 m

therefore distance traveled is 100m

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