Question

A cheetah starts from rest and accelerates at 2m/s^2 for 10 sec calculate, the final velocity and the distance travelled

Answer 1

Heya......!!!!

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Given in the question :-

• Acceleration = 2 m/s^2
• Time = 10 sec
• Initial velocity = 0 m/s. ( starts from rest ) .

Final velocity ( v ) = u + at

=> v = 0 + at
=> v = 10 × 2

=> Final velocity ( v ) = 20 m/s ★

Now distance travelled ( s )

Distance can be taken out by -

=> v^2 = u^2 + 2as

here :-

• v = 20 m/s
• u = 0
• a = 2
• s = ?

Putting the values in formulae :-

=> 400 = 2×2× s
=> 400 = 4 × s
=> 400 / 4 = s

=> Distance travelled ( s ) = 100 m ★


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Hope It Helps You ☺

Answer 2

HELLO. !!!!.......


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●GIVEN :-

Initial velocity (u) = 0m/s

Time = 10 s

Acceleration = 2 m/s^2


●Now put these values in formula , we get

v = u + at

   = 0 + 2 × 10

   = 20m/s

Here, final velocity (v) = 20 m/s
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NOW ,

2as = v2 - u2

    2 × 2s = 202 - 02

    s = 400/4

       =100m


So , distance travelled is 100 m.


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hope it helps !!!

Cheers ✌✌