Question

a cheetah starts from rest, and accelerates at 2m/s^2 for ten seconds. calculate the final velocity ?​

Answer 1

$\maltese \: \red{\mid{\underline{\overline{\textbf{Answer}}}\mid}}$

We have been given that :-

• Initial velocity of cheetah = 0 (since it starts from rest)
• Final velocity = v = ?
• Acceleration = $2 \frac{m}{ {s}^{2} }$
• Time for which accelerates = 10s.

Now we know that according to First equation of motion, the final velocity of a body in motion is equals to sum of its initial velocity and product of acceleration and time. This is represented by the expression :-

$\maltese \: \orange{\mid{\underline{\overline{\textbf{v = u + at}}}\mid}}$

In this equation :-

• v = final velocity
• u = initial velocity
• a = acceleration
• t = time

Now after inputting the known values we get :-

For this case :-

$\maltese \: v = 0 + 2(10)$

$\maltese \: v = 20 \frac{m}{s}$

Therefore the final velocity of cheetah is 20m/s.

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BY SCIVIBHANSHU

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Answer 2

Answer:

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