Question

a cheetah starts from rest, and accelerates at 2m/s^2 for ten seconds. calculate the distance travelled ?​

Answer 1

Answer:100m

Explanation:

u=0,

t=10,

a=2m/s²

S=ut+ 1/2at²

S=100m

Answer 2

Given :-

Initial velocity of the cheetah = 0 m/s

Acceleration of the cheetah = 2 m/s

Time taken by the cheetah = 10 sec

To Find :-

The distance travelled by the cheetah.

Analysis :-

Here we are given with the acceleration, time taken and the initial velocity of the car.

In order to find the displacement substitute the given values from the question using the second equation of motion and find the distance travelled by the cheetah.

Solution :-

We know that,

• u = Initial velocity
• t = Time
• s = Displacement
• a = Acceleration

Using the formula,

$\underline{\boxed{\sf Second \ equation \ of \ motion=s=ut+\dfrac{1}{2} at^2}}$

Given that,

Initial velocity (u) = 0 m/s

Acceleration (a) = 2 m/s

Time (t) = 10 sec

Substituting their values,

$\sf s=0 \times 10 +\dfrac{1}{2} \times 2 \times 10^2$

$\sf s=\dfrac{1}{2} \times 2 \times 100$

$\sf s=\dfrac{200}{2 }$

$\sf s=100 \ m$

Therefore, the distance travelled by cheetah is 100 m.