A cheetah starts from rest ,and accelerates at 2m/s for 10seconds.Calculate the final velocity and distance travelled .
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2
Distance = speed * timeD = 2*10 = 20m
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8
u=0
a=2m/s^2
t=10 s
v=u+at
=0+2*10
=0+20
=20 m/s
S= ut+1/2at^2
=0*10+1/2*2*10*10
=0+100
=100 m
Therefore, the final velocity is 20 m/s and the distance traveled is 100 m.
a=2m/s^2
t=10 s
v=u+at
=0+2*10
=0+20
=20 m/s
S= ut+1/2at^2
=0*10+1/2*2*10*10
=0+100
=100 m
Therefore, the final velocity is 20 m/s and the distance traveled is 100 m.
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