Question

A cheetah starts from rest, and accelerates at 2m/s square for 10 s .calculate (a)the final velocity. (b)the distance travelled​

Answer 1

Initial speed = u= 0 m/s

Time = t =10 s

Acceleration = a= 2m/s2

Final velocity = V= ?

From FIRST equation of motion:

V= u+at

=0+2×10

=20m/s

From Second equation of motion:

S=ut+ 1/2at^2

=0xt+(1/2 )*2×10×10

=100m

Therefore, Final velocity=20m/s and DISTANCE travelled =100m

Answer 2

u= 0m/s

a= 2m/s^2

t = 10 seconds.

a) final velocity

v = u +at

v = 0+2×10

v= 20m/s

b) distance travelled

s = ut +1/2at^2

s= 0×10 +1/2×2×(10)^2

s = 100m

Cheers!