Question

A cheetah starts from rest and accelerates at 2m/s2 for 10 seconds calculate (a)the final velocity (b)the distance travelled

Answer 1

Answer:

Step-by-step explanation:

Initial speed = u= 0 m/s

Time = t =10 s

Acceleration = a= 2m/s2

Final velocity = V= ?

From FIRST equation of motion:

V= u+at

=0+2×10

=20m/s

From Second equation of motion:

S=ut+ 1/2at^2

=0xt+(1/2 )*2×10×10

=100m

Therefore, Final velocity=20m/s and DISTANCE travelled =100m

Read more on Brainly.in - https://brainly.in/question/1247798#readmore

Answer 2

Answer:

Given:

Initial velocity,u= 0

Acceleration =2m/s^2

Time taken = 10 sec

To Find :

☆ Final velocity,v

☆distance travelled,s

Solution:

By using first equation of motion-

v= u+at

》 v = 0+2×10

》 v = 0+20

》v = 20m/s

Now,

distance travelled

By using second equation of motion :

$\bold{\mathbb{s = ut +\frac{1}{2}a{t}^{2}}}$

$\bold{\mathbb{》s = 0×10+\frac{1}{2}×2×{10}^{2}}}$

$\bold{\mathbb{》s = 0 +\frac{1}{2}×2×100}}$

$\bold{\mathbb{》s = 100}}$

__________________________

Thus,the final velocity is :

$\boxed{\boxed{\boxed{\mathbb{v = 20m/s}}}}$

And the distance travelled is :

$\boxed{\boxed{\boxed{\mathbb{s=100m}}}}$