Question

A cheetah starts from rest and accelerates uniformly at 5 m per sec square for 250 m. Calculate the time it takes to cover the distance.​

Answer 1

Answer:

Given,

$u = 0 \: m {s}^{ - 1} \\ s = 250 \: m \\ a = 5 \: m {s}^{ - 2} \\ t = \: to \: find \: \\ s = ut + \frac{1}{2} a {t}^{2} \\ \implies \: 250 = 0 \times t + \frac{1}{2} \times 5 \times {t}^{2} \\ \implies \: 5 {t}^{2} = 250 \times 2 = 500 \\ \implies \: t = \sqrt{ \frac{500}{5} } = \sqrt{100} = 10 \: s$