Question

A cheetah starts from rest, and acceleration at 2m/S2 for 10 second calculate
(a) the final velocity
(b) the distance travelled

Answer 1

here's your ans hope it helps you

Answer 2

Howdy!!

your answer is ----
Given, initial velocity u = 0 , time period t =10 sec and acceleration a = 2m/s^2

a) Let, final velocity is v
we know that-
$acceleration \: a = \frac{v - u}{t} \\ = > 2 = \frac{v - 0}{10} \\ = > v = 2 \times 10 = 20m {s}^{ - 1}$

b) according to formula --
$s = ut + \frac{1}{2} a {t}^{2} \\ = > s = 0 \times t + \frac{1}{2} \times 2 \times {10}^{2} \\ = > s = 0 + {10}^{2} \\ = > s = 100m$



hence, final velocity v = 20m/s
and distance s = 100m

hope it help you