a cheetah starts from rest and accelrates at 0.5ms2 for 10 seconds.calculqte the final velocity and the distance travelled
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I think 5ms20 I hope it is correct and helpful for you
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Use v=u+at for final velocity just see this:-
v=u+at
=0+0.5×10
=5m/s
Use s=ut+1/2at^2 for distance travelled see below:-
s=ut+1/2at^2
=0×10+1/2×0.5×10^2
=0+1/2×0.5×100
=0.5×50
=25m
v=u+at
=0+0.5×10
=5m/s
Use s=ut+1/2at^2 for distance travelled see below:-
s=ut+1/2at^2
=0×10+1/2×0.5×10^2
=0+1/2×0.5×100
=0.5×50
=25m
Nereida:
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