A cheetah starts from rest and aceretion at 2 m/s^2 for 10 sec. calculate the final velocity, the distance travelled
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initial velocity u = 0 m/s
acceleration a = 2 m/s^2
time t = 10 sec
final velocity v = ?
distance travelled S = ?
from first equation of motion,
v = u + a.t
v = 0 + 2 . 10
v = 20 m/s
now, from second equation of motion,
S = u. t + 1/2 a . t^2
S = 0 + 1/2 × 2 ×10×10
S = 100 m
acceleration a = 2 m/s^2
time t = 10 sec
final velocity v = ?
distance travelled S = ?
from first equation of motion,
v = u + a.t
v = 0 + 2 . 10
v = 20 m/s
now, from second equation of motion,
S = u. t + 1/2 a . t^2
S = 0 + 1/2 × 2 ×10×10
S = 100 m
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