a chemical manufacturer mixes 2000 gallons of a 25% exgene solution with 1000 gallons of a 40% exgene solution.The concentration of exgene in the resulting mixture
Answers
The concentration of exgene in the resulting mixture is 30%.
Step-by-step explanation:
Let the solution containing 25% exgene be denoted as “Sol 1” and the solution containing 40% exgene be denoted as “Sol 2”.
2000 gallons of Sol 1 is mixed:
The volume of exgene to be mixed from Sol 1,
= 25% of 2000
= ¼ * 2000
= 500 gallons
1000 gallons of Sol 2 is mixed:
The volume of exgene to be mixed from Sol 2
= 40% of 1000
= (2/5) * 1000
= 400 gallons
∴ The total volume of exgene in the resultant mixture will be = 500 + 400 = 900 gallons
and
The total volume of the resultant mixture = 2000 + 1000 = 3000 gallons
Thus,
The concentration of exgene in the resulting mixture is given by,
= [(total volume of exgene in the resultant mixture) / (total volume of the resultant mixture)] * 100
= [900/3000] * 100
= 30%
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Answer:30%
Step-by-step explanation: