A chemical mixtures requires two chemicals, a and b in the proportion 3:2. The mixtures is to be prepared in a tank of capacity 50 litres. Pipe a can fill the tank with chemical a in 15 minutes and pipe b can fill the tank with chemical b in 30 minutes. If both the pipes are opened when the tank is empty, then for how long should the pipes a and b run to obtain the mixture? (in minutes)
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Answer:
ans:(9,12)
chem (A) :must fill the tank by 30 litres and it takes 15 min to fill 50 litres
so, 15/50 =x/30 =>x=9
chem (B):must fill the tank with 20 litres and it takes 30 min to fill 50 litres
so, 30/50 =x/20 =>x=12
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