A CHEMICAL REACTION SHOWED THAT 10.47GRAM OF THE COMPOUND CONTAINED 6.21GRAM OF METAL” X” AND THE REST OF THE NON METAL “Y”.CALCULATE THE EMPIRICAL FORMULA OF THE COMPOUND FORMED BETWEEN “ X” AND “Y”. (ATOMIC WEIGHT OF “X”=207, “Y”= 35.5)
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contained 6.21g of metal X and the rest of a non metal Y . Calculate the molecular formula of ... Molecular weight of the compound is
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