A chemist has one solution containing 50℅ acid and a second one containing 25℅ acid. How much of each should be used to make 10 litres of a 40℅ acid solution.
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Let X litres of 50℅ solution be mixed with y litres of 25℅ solution. Then,
X + Y = 10 and 50℅ of X + 25℅ of Y = 40℅ of 10 .
=> X + Y = 10 and 50/100 × X + 25/100 × Y = 40/100 × 10
=> X + Y = 10 and X/2 + Y /2 = 4
=> X + Y = 10 --------(1)
And,
2X + Y = 16 ---------(2)
On solving (1) and (2) , we get X = 6 and Y = 4.
Hence,
6 litres of 5℅ solution is to be mixed 4 litres of 25℅ solution .
Let X litres of 50℅ solution be mixed with y litres of 25℅ solution. Then,
X + Y = 10 and 50℅ of X + 25℅ of Y = 40℅ of 10 .
=> X + Y = 10 and 50/100 × X + 25/100 × Y = 40/100 × 10
=> X + Y = 10 and X/2 + Y /2 = 4
=> X + Y = 10 --------(1)
And,
2X + Y = 16 ---------(2)
On solving (1) and (2) , we get X = 6 and Y = 4.
Hence,
6 litres of 5℅ solution is to be mixed 4 litres of 25℅ solution .
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