Question

a chemist has one solution containing 50 percentage acid and the second one containing 25 % acid how much of each should be mixed to make 10 litres of a 40 percentage acid solution

Answer 1

A chemist has one solution containing 50% (0.5) acid and the second one containing 25% (0.25)

$\textbf{Let the one solution be x and the}$ $\textbf{second one be 10-x.}$

Acid content in one solution = 0.5x ....(1)

Acid content in second one solution = 0.25 (10 - x) ....(2)

= 2.5 - 0.25x

Resulting acid = (1) + (2)

= 0.5x + 2.5 - 0.25x

= 0.25x + 2.5

$\underline{\underline{A.T.Q.}}$

0.25x + 2.5 = 4

(Resulting solution = 40% of acid solution)

0.25x = 4 - 2.5

0.25x = 1.5

x = $\dfrac{1.5}{0.25}$

$\boxed{x \:=\: 6 \:lit}$

So..

Chemist mix 6 lit. of 50% acid and 6 lit. of 25% second acid to make 10 lit. of40% acid solution.

Answer 2

plz refer to this attachment