A chemist has one solution which is 40% acid & another one is 20% acidic. How much of each solution should
mix to get 10 litres of a solution, which is 25% acidic
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Answer:
Let 20% acid be X ltr
Then 40% acid be 10-X
20X+40(10-X)= 25*10
20X+400–40X=250=-20X+400=250=-20X=-150
20X=150
X=150/20=7.5 lts
7.5 lrs of 20% acid solution need to be mixed with 2.5% acid solution to form 25% acid solution of 10 lrs.
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