Question

A chemist has one solution which is 50% acid and a second which is 25% acid.How much of each should be mixed to make 10 litres of a 40% acid solution?
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Answer 1

Given:

First solution that the chemist has is 50% acidic.

The second solution that he has is 25% acidic

To find:

How much of each should be mixed to make 10 litres of a 40% acid solution?

Solution:

Let the amount of first solution taken be x

And amount of second solution taken be y.

Then x + y = 10

So x = 10-y

Also 50% x + 25%y = 40% of 10

0.5x + 0.25y = 4

Putting x = 10-y, we get:

0.5(10-y) + 0.25y = 4

5 - 0.5y + 0.25y = 4

1 - 0.25y = 0

0.25y = 1

y = 1/0.25

y = 4 litres

Then from the relation x = 10-y

x = 10-4 = 6 litres.

Therefore the amount of 50% acidic solution is 6 litres and the amount of 40% acidic solution be 4 lires.