A chemist has two solutions of hydrochloric acid in stock.One is 50% solutionand the other is 80% solution.How much of each should be used to obtain 100ml of a 68%solution?
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Equation of total mass
X+y=100
equation for hydrochloride acid
0.5x + 0.8y = 0.68 x
X+y=100
y= 100 - x pitting this eq in the other equation
0.8X+.50(100-X)=.68 x 100
0.8X+50- 0.50X= 68
0.30X=68-50
0.30X=18
x=18/0.30
x=60 ml 80% solution is used 100 - 60=40 ml of 50% solution is used
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